Problems on Trains Practice Test Sample Paper - 1 with Answer Key and Solution [Quantitative Aptitude]- Download in PDF

Here is solved questions of Problems on Trains [quantitative aptitude] for SBI PO and IBPS exams. Questions regarding finding Problems on Train are asked in almost all entrance examinations and candidates need to practice this section very hard to score good marks and hence good position in merit list. You can also download this question paper in PDF to save it for future references or take print out.

 

Problems on Trains [Quantitative Aptitude] Model Test Paper - 1

 

Maximum Marks: 10     /      Duration: 10 Mins

Q.1. In what time will a rain 100 meters long cross an electric pole, if its speed be 144 km/hr?

A) 2.5 seconds
B) 4.25 seconds
C) 5 seconds
D) 12.5 seconds
E) None of these

Explanation (Show/Hide)

Speed = 144 km/hr = 144 * (5/18) = 40 m/sec, Distance = 100 meters
Time = Distance/Speed = 100 / 40 = 2.5 sec

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Q.2. How long does a train 110 meter long running at the speed of 72 km/hr take to cross a bridge 132 meter in length?

A) 9.8 sec
B) 12.1 sec
C) 12.42 sec
D) 14.3 sec
E) None of these

Explanation (Show/Hide)

Total distance = 110 + 132 = 242 meter
Speed = 72 km/hr = 72 * (5/18) = 20 m/sec
Time = Distance / Speed = 242/20 = 12.1 sec.

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Q.3. A train 132 m long passes a telegraph pole in 6 seconds. Find the speed of the train.

A) 70 km/hr
B) 72 km/hr
C) 79.2 km/hr
D) 80 km/hr
E) None of these

Explanation (Show/Hide)

Distance = 132 m, Time = 6 sec
Speed = Distance / Time = 132/6 m/sec = 22m/sec = 22 * (18/5) = 79.2 km/hr.

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Q.4. A train runs at the speed of 72 kmph and crosses a 250 m long plateform in 26 sec. What is the length of goods train?

A) 230 m
B) 240 m
C) 260 m
D) 270 m
E) None of these

Explanation (Show/Hide)

Let the length of train = x meter
Total distance to be covered by train = (x + 250) meter
Speed = 72 kmph = 20 m/s
Time = 26 sec.
Distance = Speed * Time = 20 * 26
=> x + 250 = 520
=> x = 270 meter.

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Q.5. A 300 meter long train crosses a plateform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the plateform?

A) 320 m
B) 350 m
C) 650 m
D) Data inadequate
E) None of these

Explanation (Show/Hide)

Length of train = 300 m, Time to cross the pole = 18 sec
Speed = 300/18 m//s
As train crosses plateform of length x meters, total distance traveled by train = (300 + x) meter
Time taken = 39 secs
Distance = Speed * time
300 + x = 300/18 * 39
x = 350 meter.

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Q.6. Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other is:

A) 9
B) 9.6
C) 10
D) 10.8
E) None of these

Explanation (Show/Hide)

S1 = 60 km/hr, S2 = 40 km/hr
D1 = 140 m = 0.14 km, D2 = 160 m = 0.16 km
Time = (L1 + L2)/ (S1 + S2) = (0.14 + 0.16)/(60 + 40)
Time = 0.3/100 hr = (0.3/100) * 3600
=> Time = 10.8

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Q.7. Two trains of equal length are running on parallel lines in the same directions at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:

A) 50 m
B) 72 m
C) 80 m
D) 82 m
E) None of these

Explanation (Show/Hide)

Let length of the train = L1 = L2 = x meters
S1 = 36 km/hr = 10 m/sec
S2 = 46 km/hr = 12.77 m/sec
T = 36 = (x + x)/(12.77 + 10) = 2x/2.77
x = 50 meters.

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Q.8. Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

A) 36
B) 45
C) 48
D) 49
E) None of these

Explanation (Show/Hide)

S1 = 60km/hr, S2 = 90 km/hr
L1 = 1.10 km, L2 = 0.9 km
Time = (L1 + L2)/(S1 + S2) = (1.10 + 0.9)/(60 + 90)
Time = 2/150 hr = (2/150) * 3600 = 48 seconds.

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Q.9. A train speeds past a pole in 15 seconds and a plateform 100 m long in 25 seconds. Its length is:

A) 50 m
B) 150 m
C) 200 m
D) Data inadequate
E) None of these

Explanation (Show/Hide)

Let length of train = x
Speed of train is = x/15
Length = Speed * Time
=> 100 + x = (x/15) * 25
=> x = 150 meters.

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Q.10. A train 110 meters long is running with a speed 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

A) 5 sec
B) 6 sec
C) 7 sec
D) 10 sec
E) None of these

Explanation (Show/Hide)

S1 = 6 kmph, S2 = 60 kmph
Avg speed = 60 + 6 = 66 kmph = 55/3 m/sec
L2 = 110 meters
T = 110 / (55/3) = 6 sec.

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