Quantitative Aptitude Practice Test Sample Paper - 1 for SBI PO 2015 with Answer Key and Solution- Download in PDF

Here is solved questions of quantitative aptitude for SBI PO and IBPS exams. quantitative aptitude and numerical ability questions are asked in almost all examinations and candidates need to practice this section very hard to score good marls and hence good position in merit list. You can also download this question paper in PDF to save it for future references or take print out.

 

Quantitative Aptitude and Numerical Ability SBI PO Model Test Paper - 1

 

Maximum Marks: 10           Duration: 6 Mins

Q.1. Three fourth of a number is equal to 60% of another number. What is the difference between the numbers?

A) 18
B) 32
C) 24
D) Cannot be determined
E) None of these

Explanation (Show/Hide)

Let first number be x, second number is y
3/4 * x = 60/100 * y
=> 5x = 3y
So x and y could have multiple values and hence we cannot determine there difference.

---

Q.2. Abhijit invested in three schemes A, B and C the amounts in the ratio of 2:3:4 respectively. If the schemes offered interest @20 p.c.p.a. 16 p.c.p.a and 15 p.c.p.a respectively, what will be the respective ratio of the amounts after one year?

A) 10 : 8 : 5
B) 12 : 14 : 15
C) 12 : 15 : 22
D) Cannot be determined
E) None of these

Explanation (Show/Hide)

Let A, B, C be 200, 300 and 400.
Adding 20 to A, it becomes 240
Adding 16% to B, ir becomes 348
Adding 15% to C, it becomes 460
Hence A: B: C = 240 : 348 : 460
= 60 : 87 : 115.

---

Q.3. A train crosses a 300 meter long platform in 38 seconds while it crosses a signal pole in 18 seconds. What is the speed of the train in km/h?

A) Cannot be determined
B) 72 km/ hr
C) 48 km/ hr
D) 54 km/ hr
E) None of these

Explanation (Show/Hide)

Let the length of train is L meters.
speed = distance / time
speed = 300 + L / 38 Eq. 1
speed = L / 18 Eq .2
From Eq.1 and Eq. 2 L = 270 meters
From Eq 2. Speed = 270 / 18 = 15 m/s
= (15 * 3600)/ 1000 = 54 km / hr.

---

Q.4. If 2x + 5y = 109 and 2x + 5 = y + 12 then y - x = ?

A) 7
B) 6
C) 5
D) 9
E) None of these

Explanation (Show/Hide)

Solving both equations
x = 12, y = 17.

---

Q.5. Four of the following five parts numbered (1), (2), (3), (4) and (5) are exactly equal. The number of the part, which is not equal to the other four parts, is your answer.

A) 45×12+60 ---(1)
B) 80% of 800 – 40 ---(2)
C) (3 / 5) of 1200 –150 ---(3)
D) 1260 / 3 + 180 ---(4)
E) 8640 / 16 + 60 ---(5)

Explanation (Show/Hide)

Value of all except (3) is 600.

---

Q.6. Certain number of pieces of an article are to be packed in boxed, such that each box contains 145 pieces. If after packing them in 32 boxed 25 pieces are left out, what was the number of pieces to be packed?

A) 4566
B) 4655
C) 4465
D) 4640
E) None of these

Explanation (Show/Hide)

Number of pieces are 145 * 32 + 25 = 4665.

---

Q.7. Which of the following set of fractions is in ascending order?

A) 13 / 15, 11 / 13, 7 / 8, 8 / 9
B) 11 / 13, 13 / 15, 7 / 8, 8 / 9
C) 8 / 9, 7 / 8, 13 / 15, 11 / 13
D) 7 / 8, 8 / 9, 11 / 13, 13 / 15
E) None of these

Explanation (Show/Hide)

Evaluating these fractions
13 / 15 = 0.86
11 / 13 = 0.84
7 / 8 = 0.87
8 / 9 = 0.88

---

Q.8. 3 Girls and 4 boys are to be seated in a row on 7 chairs in such a way that all the three girls always sit together. In how many different ways can it be done?

A) 720
B) 576
C) 144
D) 480
E) None of these

Explanation (Show/Hide)

Since three girls always sit together so we can consider them as single unit. So number of ways to arrange 4 boys and 1 unit of girl is 5!. Now we can arrange girls in 3! ways so ans is 5! x 3! = 720.

---

Q.9. In how many different ways can the letters of the word DRASTIC be arranged in such a way that the vowels always come together?

A) 720
B) 360
C) 1440
D) 540
E) None of these

Explanation (Show/Hide)

As there are 5 consonants and 2 vowels, so number of ways to arrange them so that vowels always come together is 6! x 2! = 1440 . (First we will take vowels as single unit and then arrange them mutually).

---

Q.10. Area of circle is equal to the area of a rectangle having perimeter of 50 cms, and length more than the breadth by 3 cms. What is the diameter of the circle?

A) 7 cms
B) 21 cms
C) 28 cms
D) 14 cms
E) None of these

Explanation (Show/Hide)

Let the length be x cms so breadth is (x-3).
Perimeter of rectangle = 2 ( length + breadth)
=> 50 = 2(x + x - 3) => length = x = 14, breadth = x - 3 = 11.
Area of rectangle = length * breadth = 14 * 11
Area of circle = area of rectangle
=> (22/7) x r x r = 14 * 11
=> r = 7 cms, Diameter = 2 * r = 14 cms.

---

• Click to Download this Question Papers in PDF.

• Click for More Quantitative Aptitude Question Papers.

• Click to Subscribe and Get Daily Update of Quantitative Aptitude Question Papers in your Inbox.

We have tried our best to present only  important questions with correct answer key to help you improve your Quantitative Aptitude. Any suggestion or update about any erroneous entry or answer is always appreciable. Please comment your score or any suggestion in comment section below or you can write to us at careerguide.co@gmail.com. We will be glad to help you.

---

Want to Stay in Contact !

Get new posts and updates in your inbox. Subscribe through our Feedburner Email subscription.

---

Share With your Friends !

Share

Tweet

---