Skip to main content

Simple Interest and Compound Interest (SI and CI)- Important Formulae, Tricks and Shortcuts [Quantitative Aptitude]

Here are important formulas and shortcuts to solve problems related to Simple Interest and Compound Interest. Basic knowledge regarding calculating SI and CI is important for various competitive exams like IBPS, SBI Bank PO, assistant, SSC exams, Railway exam, UPSC exams.

What is Simple Interest?


  • Suppose Ramesh borrowed 1000 rupees from Bank. This is called Principle (P)  amount.
  • Now while lending money Bank asked him  to pay extra 5% or Rs 50/1000. Here 5% is called Rate of Interest (R).
  • Ramesh has promised to pay the money back after two years with interest, so 2 years is Time period (T).
  • As Ramesh has to pay Rs. 50/1000 per year, so after two years he has to pay Rs. 100 extra. This extra money is called Simple Interest (SI).
  • After two years Ramesh will pay (1000+100) = Rs. 1100 to Bank.  Money paid back is called Amount.

Important Formulae on Simple Interest:


  • SI = (P * R * T) / 100


  • P = (SI * 100) / (R * T)


  • R = (SI * 100) / (P * T)


  • T = (SI * 100) / (P * R)

 

  • Amount = Principle + SI.




What is Compound Interest?


Taking same case we discussed above Ramesh borrowed Rs. 1000 from a Bank at 5% Rate of Interest for Time Period of 2 years, but bank has asked him to pay compound interest annually. So in this case amount will be calculated annually.

After one year amount will be P + SI = 1000 + 50 = 1050.
So for second year Principle will be 1050.
SI for second year = (1050 * 5 * 1) / 100 =  52.50
So amount after 2nd year will be P + SI =  1050 + 52.50 = 1102.50.
Hence Compound Interest (CI) he paid = 1102.50 - 1000 = 102.50.

Important Formulae on Compound Interest:


I. When CI is calculated Annually:


  • Amount = P * (1+R/100)T


  • CI = Amount - Principle


II. When CI is calculated Half - yearly:


  • Amount = P * {1+(R/2)/100}2T


  • CI = Amount - Principle


III. When CI is calculated Yearly but time is given in fraction say 2 (1/2) years ( 2 and half year).


  • Amount = P * (1+R/100)2 * {1 + ((1/2) * R)/100}

 

IV. When Rates of Interest are different for different years, say R1,%, R2%, R3% for 1st, 2nd and 3rd year.


  • Amount = P * (1 + R1/100) * (1 + R2/100) * (1 + R3/100).


V. Concept of Equal Installment when interest is compounded annually:


Let us suppose P money is borrowed for 2 years at R rate of interest and we have to return the money in 2 equal installments annually. Then the installments will be? 

If installment = X


  • P = X / (1 + R/100) + X / (1+R/100)2

 

Recommended Posts:

Comments

Popular posts from this blog

Download Previous Year Question Papers of BSNL TTA Exam Free in .PDF

Previous year question papers of BSNL Telecom Technical Assistants (TTAs) Recruitment Examination gives an insight of current year paper. Although recent year paper format is some different as previously we have to solve any two topics under specialization but this time it will be a common paper for all still previous year papers of BSNL TTA will help to check the level of exam and prepare accordingly. We have collected some best links to previous year papers of BSNL Telecom Technical Assistants (TTAs) published here to help readers get successfully through BSNL Telecom Technical Assistants (TTAs).

JEE Papers - Download JEE Mains and Advanced Previous Year Papers fully solved with detailed and complete explanation in PDF

If you are preparing for JEE Mains or JEE Advanced and have not solved previous year papers then your completion is incomplete. Previous year papers of JEE Mains and Advanced provides an insight of current year paper and also help to check our preparation level as JEE Mains and Advanced papers are a perfect example of completeness of knowledge and depth of concepts.

Download Previous Year Question Papers of Prasar Bharti Engineering Assistant and Technician Post

Previous year papers of Prasar Bharti Engineering Assistant and Technician Examinations gives an insight of current year paper. It helps students to test there skills and prepare accordingly to crack Prasar Bharti Exam easily and successfully. We have collected some best links to previous year papers of Prasar Bharti Engineering Assistant and Technician and published here to help readers get successfully through Prasar Bharti Exam.

NEET UG 2013 Counselling Schedule and Procedure for Admission to Various Medical Colleges and Institutes

NEET ( National Eligibility cum Entrance Test ) UG results has been out and every one has checked their performance in NEET -2013 test and are curious to get counselling schedule for various government medical colleges across all India, in different states, in army colleges and some reputed private medical colleges. Although it is first time that CBSE has conducted NEET - UG exam and it is a common exam for which has replaced many individual Medical college entrance tests, so no one has any confirmed idea of its further processing. NEET is shortly going to announce further counselling details on their official website and also medical colleges are also going to announce the merit list of students eligible to take part in counselling.

RBI Assistants 2015 Papers | Download Previous Year Question Papers for RBI Assistants Examination Solved Free in pdf | RBI Sample Papers

Reserve Bank of India has invited application from eligible Indian citizens for post of Assistants in RBI. There are total 504 vacancies available in different offices of India. Examination will be conducted on various dates in August 2015 in various examination centers in India. Here we have collected some links to previous year papers with Answers Key ( Solution ) of RBI Assistants examination to help students to get insight of current year papers and prepare accordingly to get through Assistant exam easily and successfully.

Maths Shortcut Tricks and Speed Calculation Methods - Download in PDF

Here we have collected some important shortcut tricks and speed calculation methods to help candidates do calculation without using pen and paper and save their time in competitive examinations. These days cracking competitive examinations needs accuracy and speed. A good speed with accuracy can take you far ahead than other candidates and improve chances of success. So it is recommended to learn fast calculation tricks and shortcuts and save your precious time and crack any exam successfully.